-5x^2-25x=15x-560

Solution for -5x^2-25x=15x-560 equation:

-5x^2-25x=15x-560

We move all terms to the left:

-5x^2-25x-(15x-560)=0

We get rid of parentheses

-5x^2-25x-15x+560=0

We add all the numbers together, and all the variables

-5x^2-40x+560=0

a = -5; b = -40; c = +560;
Δ = b2-4ac
Δ = -402-4·(-5)·560
Δ = 12800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12800}=\sqrt{6400*2}=\sqrt{6400}*\sqrt{2}=80\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-80\sqrt{2}}{2*-5}=\frac{40-80\sqrt{2}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+80\sqrt{2}}{2*-5}=\frac{40+80\sqrt{2}}{-10}
$